python怎么生成一个嵌套字典,不想使用defaultdict实现
比如原生的dict属性
test=dict()
test['a']=1 # 这个可以实现
test['x']['y']=2 # 这个就会报错
我想生成一个递归字典,如果没有这个键则创建,哪种方法能简洁点,优雅点~~多谢了
比如原生的dict属性
test=dict()
test['a']=1 # 这个可以实现
test['x']['y']=2 # 这个就会报错
我想生成一个递归字典,如果没有这个键则创建,哪种方法能简洁点,优雅点~~多谢了
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