Servlet获取ajax传递的json值
Servlet获取ajax传递的json值
其实标题可直接写为“记一件愚蠢的事”。另外声明这是只是一篇水文。
原本都用SpringMVC和ajax进行前后台的交互，今天打算试试用原始的Servlet与其进行交互。
起初是打算实现一个跳转（虽然感觉没什么意义）：
Action如下：
package per.zww.ajax.action; import java.io.IOException; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; @WebServlet("/ServletAjax") public class ServletAjax extends HttpServlet { private static final long serialVersionUID = 1L; public ServletAjax() { super(); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub this.doPost(request, response); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.getRequestDispatcher("hello.jsp").forward(request, response); } } JSP页面如下：
<%@ page language="java" contentType="text/html; charset=utf-8"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>Insert title here</title> <script src="<%= request.getContextPath() %>/js/jquery-1.7.2.min.js"></script> <script type="text/javascript"> $(function(){ $("#test").click(function(){ $.post("ServletAjax"); }); }) </script> </head> <body> <input type="button" name="test" id="test" value="测试"/> </body> </html> run运行
坑爹了，它怎么不跳转呢？！ 用firebug查看，没错啊200OK。怎么不跳转？！
坑爹了，好久没碰连ajax使用都忘了。url是发送请求的地址，若是想要想跳转需在function回调函数里面写上window.location.href="ServletAjax";
下面开始正题
其实Servlet获取ajax传递的json值很容易，只需在servlet用request.getParameter()方法即可。
Action如下：
package per.zww.ajax.action; import java.io.IOException; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; @WebServlet("/ServletAjax") public class ServletAjax extends HttpServlet { private static final long serialVersionUID = 1L; public ServletAjax() { super(); } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub this.doPost(request, response); } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String username=request.getParameter("username"); System.out.println(username); request.getRequestDispatcher("hello.jsp").forward(request, response); } } JSP页面如下：
<%@ page language="java" contentType="text/html; charset=utf-8"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>Insert title here</title> <script src="<%= request.getContextPath() %>/js/jquery-1.7.2.min.js"></script> <script type="text/javascript"> $(function(){ $("#test").click(function(){ $.post("ServletAjax",{username:"zhaoww"},function(data){ window.location.href="ServletAjax"; }); }); }) </script> </head> <body> <input type="button" name="test" id="test" value="测试"/> </body> </html> 本文由用户 jopen 自行上传分享，仅供网友学习交流。所有权归原作者，若您的权利被侵害，请联系管理员。
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