为确保php页面在后台运行，写了一个监控脚本，假设程序异常退出，那么可以自动重启。

shell脚本/usr/local/scripts/receve.sh内容：

#!/bin/bash  #funtion:keep receve.php running  PHP="/usr/local/php5/bin/php"  PROGRAM="receve.php"  #start dameo  $PHP /home/httpd/$PROGRAM >>/usr/local/scripts/phpshell/receve.out &  chpid="$!";  echo "$chpid" > /usr/local/scripts/phpshell/receve.sid  echo "child pid is $chpid"  echo "status is $?"  while [ 1 ]  do  wait $chpid  exitstatus="$?"  echo "child pid=$chpid is gone, $exitstatus" >>/usr/local/scripts/phpshell/receve.php_error.log  echo `date` >> /usr/local/scripts/phpshell/receve.php_error.log  echo "**************************" >>/usr/local/scripts/phpshell/receve.php_error.log  sleep 10  $PHP /home/httpd/$PROGRAM >> /usr/local/scripts/phpshell/receve.out &  chpid="$!";  echo "$chpid" > /usr/local/scripts/phpshell/receve.sid  echo "next child pid is $chpid"  echo "next status is $?"  done

需要保证监控脚本正常运行，在每天凌晨自动重启脚本/usr/local/scripts/restart_r.sh，写入crontab：

#!/bin/bash  echo "" >/tmp/receve_pid.txt  /bin/ps ax | /bin/grep "receve.sh" | /bin/grep -v "grep" | /bin/awk '{print $1}' >/tmp/receve_pid.txt  no1pid=`cat /tmp/receve_pid.txt | sort -r`  no2pid=`cat /usr/local/scripts/phpshell/receve.sid | sort -r`  if [ -z $no1pid ];then    echo "receve.sh pid is null, receve.sh is not running."   else      /bin/kill -9 "$no1pid"      echo "receve.sh killed"  fi  sleep 3  if [ -z $no2pid ];then    echo "receve.php pid is null, receve.php is not running."   else    /bin/kill -9 "$no2pid"    echo "receve.php killed"  fi  rm -rf /usr/local/scripts/phpshell/receve.sid   sleep 3   /usr/local/scripts/receve.sh > /dev/null &

crontab：

注意：脚本命名要避免重复，避免自己kill掉自己的进程。