| 注册
请输入搜索内容

热门搜索

Java Linux MySQL PHP JavaScript Hibernate jQuery Nginx
jopen
10年前发布

Android ListView实现任意layout

SimpleAdapter adapter = new SimpleAdapter(this, getData(),                  R.layout.timenotes_item_left, new String[] { "text1", "text2",                          "text3" }, new int[] { R.id.textView2, R.id.textView3,                          R.id.textView4 }) {              @Override              public View getView(int position, View convertView, ViewGroup parent) {                  Map itemData = (Map) getItem(position);                  int type = Integer.parseInt(itemData.get("type").toString());                  View itemView = null;                  switch (type) {                  case 0:                      Log.d("adapter", "type 0");                      itemView = View.inflate(getApplicationContext(),                              R.layout.timenotes_item_left, null);                      break;                  case 1:                      Log.d("adapter", "type 1");                      itemView = View.inflate(getApplicationContext(),                              R.layout.timenotes_item_right, null);                      break;                  default:                      Log.d("adapter", "type default");                      break;                  }                  return itemView;              }          };          ListView listView = (ListView) findViewById(R.id.listView1);          listView.setAdapter(adapter);

 本文由用户 jopen 自行上传分享,仅供网友学习交流。所有权归原作者,若您的权利被侵害,请联系管理员。
 转载本站原创文章,请注明出处,并保留原始链接、图片水印。
 本站是一个以用户分享为主的开源技术平台,欢迎各类分享!
 本文地址:https://www.open-open.com/lib/view/open1413513622544.html
ListView Android开发 移动开发