JavaScript实现方法

document.onkeydown = function(e) {      if (!e)          e = window.event;//火狐中是 window.event      if ((e.keyCode || e.which) == 13) {          document.getElementById("loginButtonId").click(); //loginButtonId为button登录按钮的ID        }  }

jQuery实现方法

$(window).keydown(function(e){      var curKey = e.which;       if(curKey == 13){          $('#loginFormId').submit(); //loginFormId为form表单的ID      }  })