每次抽取后都重新洗牌。计算10000次随机抽取可得到同花的几率。我做的比较复杂，分别累计了四种花色分别出现了几次。

import random  list=["2","3","4",'5','6','7','8','9','10',"J","Q","K","A"]  list2=["H","C","D","S"]  list3=[]  n=0  a=0  while a<4:      n=0      while n<13:          list3+=[list[n]+list2[a]]          n+=1      a+=1  i=0  r=0  d=0  c=0  s=0  h=0  while i <10000:      random.shuffle(list3)      list4=list3[0:5]      i+=1      for card in list4:          if 'D' in card:              d+=1              if d==5:                  r+=1      for card in list4:          if 'H' in card:              h+=1              if h==5:                  r+=1      for card in list4:          if 'S' in card:              s+=1              if s==5:                  r+=1      for card in list4:          if 'C' in card:              c+=1              if c==5:                  r+=1      d=0      c=0      s=0      h=0  print ('Number of natural Flushes:',r)  print('Percentage:',r/100,'%')